Let R1=R2 to minimize the effects of bias currents.
Let R4=R5, then Vsrc = the negative of the opamp output voltage.
Assuming zero current into the opamp, V- = 0 and the differential input voltage equals V+
V+ = [R2/(R2+R3)]Vout     V+ also equals Opamp output voltage divided by the gain.
1+R3/R2 = Gain
If R2 =100 ohms, R3 = 10MEG. Let R1=R2 = 100 Ohms R4=R5 = 10K to minimize opamp loading.